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    Zoran S. D.'s picture
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    Joined: Jan 14 2014


    Gravitational deflection of light

     

    To calculate the deflection of light which propagates through the medium whose refraction index is continuous, the differential form of  Snell’s law is used.

    In the case of the gravitational field, as it is given in http://home.fnal.gov/~syphers/Education/Notes/lightbend.pdf , page 2, equation (6)
    the differential form of the Snell’s law is:

    Actually, it should be:   

     

    ( so, instead of the constant   , it should be   )
    <!--[if !supportLineBreakNewLine]-->
    <!--[endif]-->

    Let us write it as   


    <!--[if !supportLineBreakNewLine]-->
    <!--[endif]-->

    If we take that the velocity is  

    ( where   ),

    then the solution of the differential equation  

    yields the deflection which is two times less than the one which is measured experimentally.

    That is not because the equation 

    is wrong (it is definitely correct, irrefutably correct), but because the Snell’s law does not take into account the following fact:

    Greater the energy of a photon, greater the refraction:

    Pic.

    The energy of a photon in a gravitation-field is

    If a photon moves away from gravitation-source, the energy of that photon decreases (gravitational red-shift, Pound-Rebka experiment).
    If a photon moves towards gravitation-source, the energy of that photon increases. And that energy increase does contribute to the photon’s path deflection.
    How much?
    Well, we have that

    and     

    So, for a photon which moves through gravitation-field, we have

    Moving towards the gravitation source,

    <!--[if !supportLists]-->-          <!--[endif]-->the change of photon’s energy is positive  

    <!--[if !supportLists]-->-          <!--[endif]-->the change of photon’s velocity is negative  

    As for   and   , they are inherently positive.

    So, we have:

     

    Now, let’s get back to the equation  

    It takes into account only the contribution of the change of the photon’s velocity. By taking into account the contribution of the change of photon’s energy, which – as shown – is equal to the contribution of the change of the photon’s velocity, the differential equation becomes:

    Upon integration, it yields

    where   is the distance of closest approach to the gravitation source.

     

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