Photon’s delay in the gravitational field
In
the post “The gem (1)”, the equation for photon’s velocity was derived, which tells
us that the photon’s velocity is not constant in the gravitational field:
Before the equation for photon’s velocity, the equation for gravitational time was derived:
From these two equations, followed the equation for the photon’s path-element:
The
Earth’s gravitational influence on the speed of light is practically
neglectable. Namely, if we take that the speed of light is , then,
according to the equation
on
the Earth’s surface it would be
Even If we encounter the influence of Sun, the velocity of a photon would be
But,
very near the Sun’s surface, it would be ,
which is
less than
.
Let’s assume that a photon travels from Earth to Mars and back, along some path which passes very near the Sun surface.
If the speed of light would be constant, the photon would travel from Earth to Mars and back for some time

it should travel longer, for some time

So, let’s calculate the

The path-element of a photon is

Along the path








The minimal value for



Hence, for our calculation, it is sufficient to take just the first two terms of the Taylor series for the function

that is,



Let us divide the photon’s route in four sub-routes:




Let us first consider the last sub-route

If we take the point to be the coordinate origin, and the direction of
-axis from
to
, we’d have



The additional short distance which our photon has to travel is in the
Earth’s vicinity. That is very far from Sun, so along the distance
we can consider that the velocity of our
photon is practically
.



The sum-time-delay along the last sub-route



The sum-time-delay along the second sub-route



The total time delay would be
Pic2
If we use these data (the data from Shapiro experiment, shown in the Pic2), we would get the time delay which Shapiro got in his measurement:

(Google: “Earth Mars Shapiro time delay”)