## A Rotational and Translational motion is standalone natural phenomenon

For this experiment, two identically thin cylinders which are initially static to the observer are taken. These cylinders are attached with internal mechanical springs that induce a repulsive action between them.

Two experiments are to be conducted.

### The first experiment. An action that repels the two cylinders is initiated. This action is induced from their center of mass. Now the cylinders are observed to move in directions opposite to each other. Based on the law of conservation of momentum, the translational velocities of the cylinders are equal. The kinetic energies of the cylinders are deduced using the below derivation: Thus it is inferred that their kinetic energies are identical.
Now, lets compare
their translational and angular momentums. It is inferred that their momentums are identical as well.
This experiment thereby proves that the two cylinders exhibit a symmetric action due to the initial repulsive inducement of their translation movement.

The second experiment. Initiate the same repulsing action as done in experiment 1, but induce the action in different positions. Induce one cylinder from its center mass and the other from its edge. On observing the movement of the cylinders, the following are noticed:

The two cylinders move in opposite directions

The cylinder that is induced from its center mass alone rotates

Assuming their linear velocities are identical according to the law of conservation of momentum, their kinetic energies are determined: From the above, equation it is inferred that their kinetic energies are not identical.
Now, as in the previous experiment, their translational and angular momentum are compared. Hence it is deduced that their translational momentums are identical. The values of the angular momentums of the two cylinders are found to deviate and the cylinder initiated from its center mass alone has an angular momentum.

Thus it is assumed that the action is not symmetric, this assumption is made by relating the action to the initial repulsing event. But this presumption fails to follow the law of conservation of angular momentum.

These deviations are however based on faulty assumptions. The linear velocities of these cylinders are not identical.

To use Newton's mechanic calculation require to simplify each body of experiment to single point object. Then these equations should apply for modeling these experiments. The Newton's mechanic equations assume the center of mass of object is a single point object for modeling. However, real body's are not single point objects. The real objects can be targeting (i.e. repulsive and collide actions) away from their center of mass.

To use Newton's mechanic equations for one type of motion, single event cannot induce two different motions in a single object. One event can trigger only one kind of motion in each object. To describe a few motions into one single object, base on first Newton's law require one unique event for each motion. Because an object should stay in one motion (First Newton's Law). Not in many motions.

The Newton's mechanic has two types of motions. Rotational and Translational motions.  Each of these motions has it's own law of momentum conservation.

The first experiment conforms to this rule, as there is only one translational motion that is induced. These cylinders have repulsive action aligned from their center of mass and each cylinder of this experiment congruent to single point object. All pieces of these cylinders conducts identical uniform motion.

In the second experiment, one of these cylinders have repulsive action aligned away from his center mass. Each piece of this cylinder conducts it's own motion with it's own cycloidal trajectory. To simplify this cylinder motion to single point object motion require to split this cylinder motion to two simple motions. Rotational and translational motions. In this case, following first Newton's law repulsive event should split to two independent events.  Base on this event splitting, the initial force should split to two independent forces. Sum of these forces should be equal to initial net force. An equations with these sub forces will cover rotation and translation motions for this cylinder as single point object. Where: Fn -net force for one event  F1,F2 - sub forces for each event  dt1,dt2 - an interval of time  m - mass of object   R - radius   I - moment of inertia of object   dv - an interval of translation velocity of object   dw - an interval of angular velocity of object.

However, to keep situation where one cylinder exhibits translational and rotational motions for one event. These two motions are thus considered as new type of motions. Therefore, this Rotational and Translational motion is standalone natural phenomenon. So it follows, the motion should have it's own  momentum and follow its own conservation of momentum.
This type of motion can be named as main type of motions. Where rotational and translational motions are parts of this main Rotational and Translational motion.

Assuming the motion has a linear and angular momentum, the total momentum of Rotational and Translational motion is: Where, Pj - linear momentum   Lk - angular momentum   Ru - unit radius

The law of conservation of momentum for the Rotational and Translational motion is: This motion has two components: rotational and translational.  How are these two correlated to the momentum? To answer this lets consider the following diagram of a rotating body. The mass of the rotating body is concentrated on its radius (Ru). An initial force Pf strikes the body which is at a distance h from the center of mass of the body. It is known that the moment of inertia is: Which implies that: Assuming this momentum is applied to the angular motion: So, the angular momentum is: Translation momentum is then equal to: Lets sum these parts and check full momentum: Adding both these equations, the total momentum is determined.

Following the new law of momentum conservation for Rotational and Translational motion, the translational and angular velocities of the cylinders have a different value on experiment 2.

Translation and angular velocities for cylinder 1 equal to: Translation and angular velocities for cylinder 2 equal to: Hence, based on the previous statement, Rotation and Translational motion corresponds to the consolidated translational and rotational motions. It is thus inferred that one of the motion is the result of the other primary complex motion.

## The above experiments are simulated.

### The experiment 1.

The simulation elicits results that relate to the theory.

Initial results: Before start Values during experiment: ### The experiment 2.

Initial results:
Before start Values during experiment:

### Let's simulate same result from experiment using additional torque.

Initial results:
Before start Values during experiment: It is inferred that the experiment 1 and 2 with additional torque produced the same results.

Both rods on experiment 1 follows these equation: Where,  mr - rod's mass, dvr -an interval of translational velocity of rod, Fi - initial pulse force, dti - an interval of time

The red rod on experiment 2 follows these equations: Where,  mr - rod's mass, dvr -an interval of translational velocity of rod, Fi - initial pulse force, dti - an interval of time, I - moment of inertia of rod, dw - an interval of angular velocity of rod, R - rod's unit radius

The red rod on experiment with additional torque follows these equations: Where  mr - rod's mass, dvr -an interval of translational velocity of rod, Fi - initial pulse force, ti1  - initial pulse force, dti2 - an interval of time of additional torque  I - moment of inertia of rod, dw - an interval of  angular velocity of rod, tau - additional torque.

These experiments use different parameters for the equations of angular momentum. For this equation the simulator for experiment 2 uses same initial pulse force. However, for experiment with additional torque simulator uses another parameter (torque).  The torque should have a pair on real world. However, the simulator can trigger unpaired torque for one body.

experiment 1 + additional torque = experiment 2

The two rods have same mass and moment of inertia.

However, in experiment 2, the rotating rod exhibits extra torque, which is simulated easily.

Observe experiment 3

The simulator applies extra translation force for rotation rod, which is not the case in real world. A fraction of applied force is spent for rotational motion (torque) then this fraction of force should be detected from the force applied for translational motion. The sum of these rotational and translational fractions of applied force should be equal to applied force for non-rotating rod. (3-rd Newton’s law)

The translational velocities of these rods should vary. But they are observes, to be equal on simulator. Because simulator is unaware about Rotational and Translational motion and hence, the independent rotational and translational motions make it difficult to make inferences from experiment 2. The classical mechanics should include new standalone translational and rotational motion as new type of motion to describe natural phenomenon correctly.

## The following are the animations recorded for experiment 2:

(click on image to see animation)

This animation follows classical mechanics laws:     ## The Natural Experiment 2.

These three  successful experiments were conducted with 2 pencils.

In these experiments pencils with rotation movement have lower velocity than pencils without rotation.

### Equipment:

Two pencils, thread and thin rubber band 3''

The rubber band is repulsing 2 objects (2 pencils).

The mass of the rubber band is much less that the mass of the pencil ### The following are the snapshots of the experiment dynamics.    Links to experiments movies (avi files)
Experiment 2_1
Experiment 2_2
Experiment 2_3
Links to experiments pictures (zip files)
Experiment 2_1
Experiment 2_2
Experiment 2_3