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    The Quote Of The Week - A Solution To Every Problem
    By Tommaso Dorigo | September 13th 2013 04:55 AM | 11 comments | Print | E-mail | Track Comments
    About Tommaso

    I am an experimental particle physicist working with the CMS experiment at CERN. In my spare time I play chess, abuse the piano, and aim my dobson...

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    "For every complex problem, there is a solution that is simple, neat and wrong"

    H.L. Mencken

    Comments

    Vladimir Kalitvianski
    A famous example - renormalization. If in your theory you obtain f(x), and in experiment you obtain g(x), you do not discard your theory. Instead, you make "touch with reality": you write f(x)=g(x)+[f(x)-g(x)] and discard the expression in the square brackets (the expression is "absorbed"). You do so because your theory must describe the reality, thus f(x) is in fact g(x). You can present it as a physical constraint imposed on the theory. Hence, you obtain g(x) in your theory which is, of course, a great success of principles. Simple, neat, and wrong.
    Oy vey. Vladimir, please read Chapter 7 of Peskin and Schroeder.

    Vladimir Kalitvianski
    Yes, I am reading: "The quantity m is the exact mass of a single particle - the exact energy eigenvalue at rest."   It means, in this theory, which is, of course, implied to be a correct theory.

    Then: "This quantity will in general differ from the value of the mass parameter that appears in the
    Lagrangian. We will refer to the parameter in the Lagrangian as m_0, the bare mass and refer to m as the physical mass of the boson. Only the physical mass m is directly observable.
    "   It means, if we leave m in our equations, our results will be wrong. So we subtract the wrong corrections to m, but we present it as "absorbing" them by m_0 to obtain m.

    There was no m_0 in nature, nor in our theory project. We just advanced a wrong interaction (self-action), we obtained wrong corrections (original coefficients of equations changed), and in order to make ends meet, we blame the original m to be m_0 (!?) and at the same time we say that our corrections to it are right! This is exactly cheating described in my previous answer.

    Interaction in QFT should not change the equation coefficients, it should change the occupation numbers. If one fails to obtain the occupation number dynamics, it is not a nature property, but a one's fault.
    That's simply because a theory needing (infinite) renormalization is an effective theory...
    So, in a way, it's the thery's fault. Anyone who is in a minimal field know agrees on this: nothing fancy or conspirational.

    Vladimir Kalitvianski
    Dear anbar,

    Indeed, nothing fancy or conspiratorial. You have just to believe in bare particles and you have to say: "As long as we do not know physics of short distances, our theory is obliged to be stuffed with wrong results, but it is OK, - we know how to obtain good results from bad ones, see the universal renormalization prescription". Simple, neat, right, and unique!

    Anyone agrees but me. Highly energetic excitations, right or wrong, are not excited, sorry for pun. Only in wrongly made theories they cause problems in any calculation, even for a free motion.
    Vladimir, you don't seem to be getting the point: the theory being effective is the very reason why you don't have to believe in bare particles... They are just a computational tool

    Vladimir Kalitvianski
    In QFT they (their constants) are a computational tool serving to "absorb" perturbative corrections, right? So these perturbative corrections are wrong if one gets rid of them with help of inventing bare parameters in course of our calculations. Read my opus here.
    So you're saying that loop corrections are wrong, right? Therefore there is no Higgs decay in two photons, right?
    Please, can you explain me the observation of the H -> γγ made by ATLAS and CMS?

    Vladimir Kalitvianski
    Why do you appeal to Higgs decays? Let us consider QED where loops are present everywhere, even in a free motion description. What do loops do to a free motion of an electron?
    Higgs decay in two photons is an impossible process without loop corrections, still require renormalization to come up with a finite results. What's wrong with this example?
    The Standard Model is a coherent theory, if renormalization is wrong for the photon or electron self-energy, than it's wrong also for Higgs decay.
    If you prefere QED, then let's talk about the anomalous magnetic moment of the muon, verified experimentally with more than 10 significant digits: it's only a coincidence that renormalization in this case works?
    Or we can talk about the Lamb shift: another incredible coincidence in which a wrong theory, renormalization, give us the correct result.

    Vladimir Kalitvianski
    You touched the very main question: if renormalization is wrong, then why does it work? Can it be another incredible coincidence or it is the true feature of interactions?

    My answers are simple ant right:

    1) We write a wrong interaction because we use analogy rather than physics to write it in case of completely coupled systems,

    2) We remove the wrong part of our interaction from results by hand, because otherwise it just does not work. This is called renormalization. We force our wrong results to be right. It is not a calculation, but a modification of calculation results. Pretext? Our theory MUST describe and DESCRIBES reality. Another pretext - it luckily works!

    3)  Such a prescription only "works" in very rare cases (all the others are non renormalizable), and its working is a fluke.

    I showed all this on a simple example of coupling two equations: our initially wrong ansatz, our wrong results, and our way of obtaining good results from bad ones. My model is exactly solvable, so you can see that success of renormalization is a fluke and there is nothing physical behind its success.