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    Electroweak Symmetry And The Chocolate Interaction
    By Tommaso Dorigo | April 18th 2010 10:13 AM | 14 comments | Print | E-mail | Track Comments
    About Tommaso

    I am an experimental particle physicist working with the CMS experiment at CERN. In my spare time I play chess, abuse the piano, and aim my dobson...

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    Analogies are a powerful way to explain complicated scientific concepts. I use them as much as I can whenever I describe particle physics in this blog or when I give a outreach talk in a school. However, good ones are not always easy to find. One usually needs examples from everyday life, which are simple to describe and which do not possess distracting features.

    Today I wish to try my luck with you, to see if you come up with an analogy which is better than the one I could find to explain a feature of weak interactions. I must say I am not dissatisfied with my own find, but it is always good to subject oneselves to external judgement.

    You probably know, if you read this blog, that photons are mass-less particles carrying the electromagnetic interaction, while W and Z bosons are very massive particles carrying the weak interaction. A stark disfference in the phenomenology of electromagnetic and weak interactions at low energy is that the former have a infinite range, while the latter have a very short range of action. Another is the very reason why W and Z bosons carry the interaction we call "weak": at low energy, the strength of the weak force is much smaller than that of the electromagnetic force.

    The fact that a massive particle has a short range of action may probably be easy to explain; harder is to let our listeners grasp the property that a force brought about by a massive body must be less intense. This in the subatomic world is due to the much smaller probability of emission of these massive bodies; and it is not easy to find a real-life analogue of such a feature.

    Below is the analogy I came up with. If you have a better one, please share it in the comments thread!

    The large mass of W and Z particles is the reason why weak forces are called that way: the mass of these vector bosons is a hindrance to their ability to mediate long-range interactions, and a parameter which determines the interaction strength. To understand how a massive mediator may be less effective than a mass-less one, take a cup of hot chocolate and a raw chocolate bar: the former disperses around with its vapour very small, light-weight particles, which you can easily smell from a distance; the latter can only release a small speck of solid chocolate if you get very close and inhale powerfully.

    The speck is much more massive than the corpuscles evaporating from the cup, and is thus incapable of carrying the chocolate interaction far away; furthermore, even at small distance the experienced chocolate smell from the bar is way less intense, because of the small rate at which the bar releases a speck of chocolate when you sniff it!

    The behaviour of the smell of the cup and the bar when sniffed may be likened to the behaviour of electromagnetic and weak interactions at low energy: the former interaction will appear much more intense. Now, however, let us imagine for the sake of arguing that we construct a computerized sniffer that analyzes the odour of solid as well as liquid materials. It works by taking the material under test, vaporizing it, and analyzing the absorption lines of the produced vapour. Such a device will find that cup and bar of chocolate have the same intensity of chocolate smell. Likewise, electromagnetic and weak interactions become equally strong at very high energy, once the different mass of chocolate particles and solid specks -pardon, of photons and W/Z bosons- becomes irrelevant.

    Comments

    Interesting as a mnemonic, but very untrue, so I don't like it. The reason why solid bar has less intensive smell is because it is cold, meaning there are very few molecules emitted due to thermal fluctuations. On the other hand, in the hot liquid there are molecules flying out all the time. But the mass of the smell carriers is precisely the same in both cases. You could argue that chocolate is a complex chemical compound, but the argument would also work for water vapor evaporating/sublimating from water/ice.

    By the way, I usually don't like analogies at all, because they always break up and when one tries to fix them one is always creating even more problems than one solvel. In the case of weak interactions I think it's plenty clear to explain the effects as they are. The qualitative rules of QFT and their basic consequences are just so simple that it's needless to create analogies that take as much time to explain and moreover are just incorrect. Which is also what Feynman says in his Strange theory of light and matter -- he tells us that usually simplicity of theories as explained to layman audience is only achieved by lots of misinformation and mystification. And he goes on to explain QED as it really is (albeit he gives just a qualitative picture) and the book is well accesible even at high school level.

    dorigo
    Hmm, Marek, Feynman loved analogies. He often used them to communicate science to the public. One of the best explanation of how physicists in their observation of Nature derive laws, observe exceptions, and are lead to investigate further is the analogy with the movement of pieces in a chessboard, which -if you have not yet seen- I invite you to watch here.

    Besides, it is absolutely not easy to explain the difference between electromagnetic and weak interactions to high-school students or laymen. You probably have no experience in outreach if you hold the opinion you described.

    Cheers,
    T.
    Ok, I agree there are better and worse analogies and chess is one of the better ones. Nevertheless Feynman never produced a misleading and far-fetched analogy as you just did, or at least I am not aware of it. If I didn't know about electroweak interactions already, I don't think I would get anything useful from your chocolate example. Whereas just explaining that heavy objects are harder to produce (giving a bit of introduction into probabilities first) is as clear as it can be.

    And I think you underestimate the intellect of an average human, if you think they wouldn't be able to comprehend qualitative features of QFT as it is. More so, if intended audience are people interested in these things (which I guess they would be, otherwise they wouldn't attend the seminar).

    dorigo
    Marek, popularization is about skipping the "introduction into probabilities" or similar commendable but unrealistic attempts. The qualitative features of QFT can be explained and this blog is successful in part because I do that; but there are limits. Analogies allow you to be listened by those that would otherwise not listen to you or get convinced that "the matter is too hard".

    No, I do not underestimate the intellect of humans, I instead know what is the typical attention span of many on difficult concepts.

    Anyway, I accept your criticism on my text. I would have preferred an alternative attempt, though.

    Cheers,
    T.
    Ok, I see what you mean. I meant no offense. I wish you many successful seminars.

    lumidek
    Dear Tommaso, first of all, the statement that "forces mediated by heavier particles are weaker" is only valid at long distances. At short distances, below the electroweak length, they're equally strong as electromagnetism - that's a part of what the electroweak unification means. Electrons and neutrinos get unified, too: they interact with the same strength....

    Your chocolate musings sound bizarre to me. What is really happening in the weak interactions is that one borrows energy to create a virtual W/Z boson, and most processes based on this process are decays, anyway. The reason why "heavy particle has a small effect" is not counterintuitive is because the heavy particle is not really there to start with: it's just a virtual particle - a possible temporary step in a longer process.

    So you can compare this borrowing of the energy for virtual W/Z bosons to the borrowing of the money. The borrowing of small amount of money - light particles - is everywhere and helps people to buy the kitchen blender or a car or a house, so it has lots of impacts. Borrowing much more money is less likely, so you can only get a loan if you're very lucky. 

    Of course, if you borrow USD 90 billion (or 90 billion eV) for a W-boson, you won't be able to pay the debt back, so eventually you will decay, much like the neutron. But such processes rarely occur because banks usually don't give USD 90 billion loans to [insert a juicy description of yourself]. That's why particles decaying because of heavy virtual particles - big loans - are much more long-lived.

    dorigo
    Hi Lubos,

    I disagree that what happens is the borrowing of energy to create a boson. Energy is not borrowed, but transferred. The boson is virtual -highly so- and thus it carries an energy much smaller than its nominal rest mass.

    Cheers,
    T.
    Also, to continue with Lubos' analogy, if you borrow a couple of trillions, you're suddenly too "big to fail", and even though you don't pay anyone back, you attract even more money. But I guess you don't want to popularize the black hole scare further, right?

    What about balls and gravitation? If I'm standing on the surface of a boiling lake composed of a) tennis balls and b) cannon balls, and I want to transfer momentum to someone, the results also depend very much on distance. If she's close, throwing cannon balls will give much more oomph. If she's far away, all my cannon balls decay uselessly (Back to the sea of cannon balls I picked them out of, if you like Dirac), but the tennis balls might still work. In the limit, I can throw weightless balls infinitely far (Oh, but what about classical momentum? I hope nobody asks!).

    lumidek
    Dear Thomas,...

    a funny comment. Up to the Planck masses, Nature doesn't obey the rules of nepotic would-be capitalism and socialism. Things are simply never too big to fail.

    But let's admit, even Nature starts with these mis-policies above the Planck masses. When elementary objects grow to masses above M_{Planck}, they become too big to fail, and the Hawking decay is slowing down as they grow even bigger. ;-)

    On the other hand, I think that all experts in quantum gravity would agree that it would be a kind of double-counting to include the effects of virtual (generic) black holes. By some UV/IR connection, all such things must be already included in the exchange of virtual low-energy stuff, so even if the virtual black holes added a big effect, we shouldn't count it again.

    Cheers
    Lubos
    dorigo
    Hi Thomas,

    thank you for your idea. I think it would be hard to include the concept of the unstable nature of weak interaction carriers in the picture. To my mind, it complicates matters. I still like the real-life example I gave better...

    Cheers,
    T.
    You're right, the boiling lake will probably confuse your school audience more than it will enlighten. Anyway, while I like the balls vs mediator particles analogy, I initially missed see that your explanation goes on to include electroweak unification, which doesn't arise naturally in the balls scenario. Maybe if there are a great many people, all throwing balls around, you lose track of the type of ball hitting you after a couple of hits to the head? No, I give up and have at least learned something about the limits of analogies.

    I dunno. The things that interact with receptors in your nose, namely whatever volatile compounds give chocolate its aroma, are all roughly the same size. It's not the chocolate bar or a splash of hot chocolate that's hitting you in the face, after all. If I were to reverse your analogy, I might say a steaming cup of hot chocolate is analogous to a very bright spotlight, whereas the chocolate bar is like a very dim flashlight. The volume of chocolate aroma is thus a bit like the amplitude of light energy.

    Also, when we talk the relative strengths of the interactions (EM or weak), I understand that the rate of photon exchange is going to be much greater than W or Z exchange, so over a span of time a particle coupled to the former force is going to feel a greater cumulative pull than one coupled to the latter force. But what about the impact of each virtual particle exchange? I know force strength is a function of the frequency of particle exchange, but would a virtual W or Z be expected to pack more of a punch than your average virtual photon? I assume scattering of particles due to exchange of virtual bosons is a function of the momentum of those virtual force-carriers. W's and Z's must have enormous momentum compared to the average photon, right?

    dorigo
    Hi anon, no, the q^2 in the boson propagator is what matters, so the exchange of a photon need not be weaker than that of a massive body. In this sense the analogy actually breaks down because a big speck of inhaled chocolate produces an intense response. Cheers, T.
    kuday
    I love analogies and chocolate, so it seems like a perfect combination for me. Exploring these kind of pedagogical ways are so important in teaching physics that only a few successful physicist could do it. Congratulations.
    I remember G.Dvali has explained the range of massive fields in a similar way at Cern Summer school Lectures last year. His lectures were wonderful, since he can tell almost everything without using complicated formulas. He told that W and Z massive bosons are like fat men. The fatter they are, the smaller hands they have. :)) Above explanation with chocolate is much better than this. Thanks!